Abs(x+1)=x^2-5

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Solution for Abs(x+1)=x^2-5 equation: 


Simplifying
Abs(x + 1) = x2 + -5

Reorder the terms:
bsA(1 + x) = x2 + -5
(1 * bsA + x * bsA) = x2 + -5
(1bsA + bsxA) = x2 + -5

Reorder the terms:
1bsA + bsxA = -5 + x2

Solving
1bsA + bsxA = -5 + x2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Reorder the terms:
5 + 1bsA + bsxA + -1x2 = -5 + x2 + 5 + -1x2

Reorder the terms:
5 + 1bsA + bsxA + -1x2 = -5 + 5 + x2 + -1x2

Combine like terms: -5 + 5 = 0
5 + 1bsA + bsxA + -1x2 = 0 + x2 + -1x2
5 + 1bsA + bsxA + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
5 + 1bsA + bsxA + -1x2 = 0

The solution to this equation could not be determined.

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